💻 Armstrong Number

def is_armstrong(n):
    digits = str(n)
    power  = len(digits)
    total  = sum(int(d) ** power for d in digits)
    return total == n, total

def all_armstrong_upto(limit):
    return [n for n in range(1, limit+1) if is_armstrong(n)[0]]

print("=== Armstrong Number Checker ===")
print("Armstrong: har digit^n ka sum = number itself")
print("Example: 153 = 1^3 + 5^3 + 3^3 = 1+125+27 = 153
")

while True:
    print("1. Number Armstrong hai ya nahi")
    print("2. Range mein sab Armstrong numbers")
    print("3. Famous Armstrong numbers dekho")
    print("4. Step-by-step calculation")
    print("5. Baahar jao")
    ch = input("Choice: ")
    if ch == "1":
        n      = int(input("Number: "))
        result, total = is_armstrong(n)
        digits = str(n)
        power  = len(digits)
        if result:
            print(f"{n} ARMSTRONG number hai!")
        else:
            print(f"{n} Armstrong NAHI hai! (Sum = {total})")
    elif ch == "2":
        limit  = int(input("Limit (max 10000): "))
        result = all_armstrong_upto(min(limit, 10000))
        print(f"Armstrong numbers upto {limit}: {result}")
    elif ch == "3":
        famous = [1, 2, 3, 4, 5, 6, 7, 8, 9,
                  153, 370, 371, 407,
                  1634, 8208, 9474]
        print("Famous Armstrong numbers:")
        for n in famous[:10]:
            print(f"  {n}")
    elif ch == "4":
        n      = int(input("Number: "))
        digits = str(n)
        power  = len(digits)
        parts  = [f"{d}^{power}={int(d)**power}" for d in digits]
        total  = sum(int(d)**power for d in digits)
        print(f"
{n} ka check:")
        print(f"  Digits: {list(digits)}")
        print(f"  Power: {power}")
        print(f"  Calculation: {' + '.join(parts)}")
        print(f"  Sum = {total}")
        print(f"  {n} {'==' if total==n else '!='} {total} => {'Armstrong!' if total==n else 'Not Armstrong'}")
    elif ch == "5":
        break